('CID110783068', 2),AHA047
('CID110783068', 2),AHA047
('CID100445754', 1),AHA047
ldiff: defaultdict(<type 'list'>, {'CID110783068': [0, 0], 'CID100445754': [0]})
f1: [0, 0]
f2: [0]
c1: Counter({0: 2})
c2: Counter({0: 1})
The chosen was ... CID110783068