('CID100090966', 3),MMDA
('CID100090966', 3),Mmda 2
('CID100090966', 3),MMDA 2
('CID100026175', 3),Mmda
('CID100026175', 3),MMDA
('CID100026175', 3),(+-)-MMDA
ldiff: defaultdict(<type 'list'>, {'CID100090966': [0, 2, 2], 'CID100026175': [0, 0, 5]})
f1: [0, 2, 2]
f2: [0, 0, 5]
c1: Counter({2: 2, 0: 1})
c2: Counter({0: 2, 5: 1})
The chosen was ... CID100090966