('CID109839500', 2),pd150606
('CID109839500', 2),PD150606
('CID100004711', 1),pd150606
ldiff: defaultdict(<type 'list'>, {'CID100004711': [0], 'CID109839500': [0, 0]})
f1: [0, 0]
f2: [0]
c1: Counter({0: 2})
c2: Counter({0: 1})
The chosen was ... CID109839500