('CID100001633', 2),su4984
('CID100001633', 2),SU4984
('CID100005306', 1),su4984
ldiff: defaultdict(<type 'list'>, {'CID100001633': [0, 0], 'CID100005306': [0]})
f1: [0, 0]
f2: [0]
c1: Counter({0: 2})
c2: Counter({0: 1})
The chosen was ... CID100001633